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<title>Difference of Two Cubes</title>
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<h1 align="center">Difference of Two Cubes</h1>
<p align="center"><i>There is a <b>special case</b> when multiplying polynomials that produces this: <b>a<sup>3</sup> &minus; b</b></i><b><i><sup>3</sup></i></b></p>
<h2>Polynomials</h2>
<p>A <a href="polynomials.html">polynomial</a> looks like this: </p>
<div class="beach">
<table border="0" align="center" cellpadding="5">
<tr align="center">
<td><img src="images/polynomial-1var-example.svg" alt="polynomial 2x^4+6x-5" /></td>
</tr>
<tr align="center">
<td>example of a polynomial<br /></td>
</tr>
</table>
</div>
<h2>Difference of Two Cubes</h2>
<p>The <b>Difference of Two Cubes</b> is a special case of <a href="polynomials-multiplying.html">multiplying polynomials</a> : </p>
<div class="def">
<p align="center" class="large">(a&minus;b)(a<sup>2</sup>+ab+b<sup>2</sup>) = a<sup>3</sup> &minus; b<sup>3</sup></p>
</div>
<p>It comes up sometimes when solving things, so is worth remembering.</p>
<p>And this is why it works out so simply (press play):</p>
<script type="text/javascript">playerMain("images/difference-cubes.txt",600,200);</script>
<h2>Example from Geometry:</h2>
<p>Take two cubes of lengths x and y:</p>
<p><img src="images/polynomial-cubes-a.gif" alt="polynomial cubes" width="248" height="127" /></p>
<p>The larger &quot;x&quot; cube can be split into four smaller boxes (cuboids), with box <b>A being a cube of size &quot;y&quot;</b>:<br />
</p>
<p><img src="images/polynomial-cubes-b.gif" alt="polynomial cubes" width="657" height="133" /></p>
<p>The volumes of these boxes are:</p>
<ul>
<li>A = y<sup>3</sup></li>
<li>B = x<sup>2</sup>(x &minus; y)</li>
<li>C = xy(x &minus; y)</li>
<li>D = y<sup>2</sup>(x &minus; y)</li>
</ul>
<p>But together, A, B, C and D make up the larger cube that has volume x<sup>3</sup>: <br />
</p>
<table border="0" align="center">
<tr>
<td align="right" class="larger">x<sup>3</sup></td>
<td class="larger">&nbsp;=&nbsp;</td>
<td class="larger"> y<sup>3</sup> + x<sup>2</sup>(x &minus; y) + xy(x &minus; y) + y<sup>2</sup>(x &minus; y)</td>
</tr>
<tr>
<td align="right"><span class="larger">x<sup>3</sup> &minus; y<sup>3</sup></span></td>
<td><span class="larger">&nbsp;=&nbsp;</span></td>
<td class="larger">x<sup>2</sup>(x &minus; y) + xy(x &minus; y) + y<sup>2</sup>(x &minus; y)</td>
</tr>
<tr>
<td align="right"><span class="larger">x<sup>3</sup> &minus; y<sup>3</sup></span></td>
<td><span class="larger">&nbsp;=&nbsp;</span></td>
<td class="larger"> (x &minus; y)(x<sup>2</sup> + xy + y<sup>2</sup>)</td>
</tr>
</table>
<p>Hey! We ended up with the same formula! Thank goodness.</p>
<h2>Sum of Two Cubes</h2>
<p>There is also the &quot;Sum of Two Cubes&quot;</p>
<p>By changing the sign of <span class="large">b</span> in each case we get:</p>
<div class="def">
<p align="center" class="large">(a+b)(a<sup>2</sup>&minus;ab+b<sup>2</sup>) = a<sup>3</sup> + b<sup>3</sup> </p>
</div>
<p>(note the minus in front of &quot;ab&quot; also)</p>
<p>&nbsp;</p>
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